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Degree 3 serendipity on a interval

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In this example:
\(\displaystyle l_{0}:v\mapsto v(0)\)

\(\displaystyle \phi_{0} = - 10 x^{3} + 18 x^{2} - 9 x + 1\)

This DOF is associated with vertex 0 of the reference element.
\(\displaystyle l_{1}:v\mapsto v(1)\)

\(\displaystyle \phi_{1} = x \left(10 x^{2} - 12 x + 3\right)\)

This DOF is associated with vertex 1 of the reference element.
\(\displaystyle l_{2}:v\mapsto\displaystyle\int_{R}(1 - s_{0})v\)
where \(R\) is the reference element;
and \(s_{0}\) is a parametrisation of \(R\).

\(\displaystyle \phi_{2} = 12 x \left(5 x^{2} - 8 x + 3\right)\)

This DOF is associated with edge 0 of the reference element.
\(\displaystyle l_{3}:v\mapsto\displaystyle\int_{R}(s_{0})v\)
where \(R\) is the reference element;
and \(s_{0}\) is a parametrisation of \(R\).

\(\displaystyle \phi_{3} = 12 x \left(- 5 x^{2} + 7 x - 2\right)\)

This DOF is associated with edge 0 of the reference element.